Skip to main content

Time Series




Time Series in R
Using the data set Tampa weather to create a time series function. 

R CODE:
##create data for the rainfall
rain2015 <- c(-3,41,33,6,14.6,28.2,21.4,1.81,15.60,0.52,2.90)
rain1995 <- c( 0 ,60, 46,16,21.2, 32.6, 26.9, 3.66, 24.20, 0.93, 5.60)
##storing time series and printint it out
rrain2015 <- ts(rain2015, )
rrain1995<- ts(rain1995)
rrain1995
 rrain2015

##set up time series for the year of rain fall
rain2015.timeseries <- ts(rain2015,start = c(2015,1),frequency = 12)



##print the year for rainfall 2015
print(rain2015.timeseries)


##plot the rain fall for 2015 year
plot.ts(rrain2015)
plot.ts(rain2015.timeseries)

lograin2015 <- log(rain2015)
plot.ts(lograin2015)

#plot multiple time series
combined.rainfall <-  matrix(c(rain1995,rain2015),nrow = 12)

rainfall.timeseries <- ts(combined.rainfall,start = c(2015,1),frequency = 12)

print(rainfall.timeseries)
plot(rainfall.timeseries, main = "Multiple Time Series")

Comments

Post a Comment

Popular posts from this blog

Project: Building a Predictive Model

You are a data scientist working for University of South Florida. Your boss wants to develop a predictive model to automatically make a prediction on students' graduation rates based on several factors (variables). You have College dataset ( College.csv ) , which is also available in the ISLR package.  R code Studio
Post a Comment
Read more

Information Architecture: High Fidelity Design

 For my Group  Project we had to create a low fidelity and high fidelity website design that focus on education and student as well as parents or those involves in education.     
Post a Comment
Read more

Confidence Interval Estimation And introduction to Fundamental of hypothesis testing

1. x̄ = 85 and σ = 8, and n = 64, set up a 95% confidence interval estimate of the population mean μ.  Z= 1-(0.05/2) = 1.96 Sample mean= x-bar = 85 Z*s/sqrt(n) = (1.96*8)/sqrt(64) = 1.96 CI= 85 – 1.96= 83.04 CI= 85- 1.96= 86.96 (83.04, 86.96) 2. If  x̄ = 125, σ = 24 and n = 36, set up a 99% confidence interval estimate of the population mean μ.  Z= 1- (0.01/2) = 0.995= 2.57 Z*s/sqrt(n) = 125 - (2.57*8/sqrt(36) = 3.42-125= 121.58 Z*s/sqrt(n) = 125 + (2.57*8/sqrt(36) = 3.42+125= 128.42 3. The manager of a supply store wants to estimate the actual amount of paint contained in 1-gallon cans purchased from a nationally known manufacturer. It is known from the manufacturer's specification sheet that standard deviation of the amount of paint is equal to 0.02 gallon. A Random sample of 50 cans is selected and the sample mean amount of paint per 1 gallon is 0.99 gallon.  3a. Set up a 99% confidence inter...
Post a Comment
Read more